Base | Representation |
---|---|
bin | 10011001010001101100… |
… | …100100010110110001111 |
3 | 11122212110120100010200101 |
4 | 103022031210202312033 |
5 | 133032432100104301 |
6 | 2444504232511531 |
7 | 164060306130106 |
oct | 23121544426617 |
9 | 4585416303611 |
10 | 1316635159951 |
11 | 468422250071 |
12 | 19320a54b5a7 |
13 | 97209639a57 |
14 | 47a22a1703d |
15 | 243ae581701 |
hex | 1328d922d8f |
1316635159951 has 2 divisors, whose sum is σ = 1316635159952. Its totient is φ = 1316635159950.
The previous prime is 1316635159949. The next prime is 1316635160023. The reversal of 1316635159951 is 1599515366131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1316635159951 - 21 = 1316635159949 is a prime.
Together with 1316635159949, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 1316635159892 and 1316635159901.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1316635159351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658317579975 + 658317579976.
It is an arithmetic number, because the mean of its divisors is an integer number (658317579976).
Almost surely, 21316635159951 is an apocalyptic number.
1316635159951 is a deficient number, since it is larger than the sum of its proper divisors (1).
1316635159951 is an equidigital number, since it uses as much as digits as its factorization.
1316635159951 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3280500, while the sum is 55.
The spelling of 1316635159951 in words is "one trillion, three hundred sixteen billion, six hundred thirty-five million, one hundred fifty-nine thousand, nine hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •