Base | Representation |
---|---|
bin | 11101111110110110000110… |
… | …101101010010010110011000 |
3 | 122021212220000001102111010122 |
4 | 131332312012231102112120 |
5 | 114240411440022114310 |
6 | 1144240331232332412 |
7 | 36526501355631551 |
oct | 3576660655222630 |
9 | 567786001374118 |
10 | 131862050973080 |
11 | 3901942215734a |
12 | 129578ba0a4108 |
13 | 58766cc13abbc |
14 | 247c22b987328 |
15 | 103a07b935555 |
hex | 77ed86b52598 |
131862050973080 has 32 divisors (see below), whose sum is σ = 296694587826000. Its totient is φ = 52743936276096.
The previous prime is 131862050973073. The next prime is 131862050973083. The reversal of 131862050973080 is 80379050268131.
131862050973080 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131862050973083) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25209755 + ... + 29987594.
Almost surely, 2131862050973080 is an apocalyptic number.
131862050973080 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131862050973080 is an abundant number, since it is smaller than the sum of its proper divisors (164832536852920).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131862050973080 is a wasteful number, since it uses less digits than its factorization.
131862050973080 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55257083 (or 55257079 counting only the distinct ones).
The product of its (nonzero) digits is 2177280, while the sum is 53.
The spelling of 131862050973080 in words is "one hundred thirty-one trillion, eight hundred sixty-two billion, fifty million, nine hundred seventy-three thousand, eighty".
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