Base | Representation |
---|---|
bin | 11000100100100011… |
… | …10001100100000000 |
3 | 1021001100020020100120 |
4 | 30102101301210000 |
5 | 204004014114412 |
6 | 10020552420240 |
7 | 644620223016 |
oct | 142221614400 |
9 | 37040206316 |
10 | 13191551232 |
11 | 565a317762 |
12 | 26819a7680 |
13 | 1322c8b522 |
14 | 8d1d8c8b6 |
15 | 52318cb8c |
hex | 312471900 |
13191551232 has 72 divisors (see below), whose sum is σ = 35965161120. Its totient is φ = 4289925120.
The previous prime is 13191551227. The next prime is 13191551357. The reversal of 13191551232 is 23215519131.
It is a junction number, because it is equal to n+sod(n) for n = 13191551193 and 13191551202.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 177982 + ... + 240957.
Almost surely, 213191551232 is an apocalyptic number.
13191551232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
13191551232 is an abundant number, since it is smaller than the sum of its proper divisors (22773609888).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13191551232 is an equidigital number, since it uses as much as digits as its factorization.
13191551232 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 418999 (or 418985 counting only the distinct ones).
The product of its digits is 8100, while the sum is 33.
It can be divided in two parts, 1319 and 1551232, that added together give a palindrome (1552551).
The spelling of 13191551232 in words is "thirteen billion, one hundred ninety-one million, five hundred fifty-one thousand, two hundred thirty-two".
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