Base | Representation |
---|---|
bin | 1011111111111111111100… |
… | …1101111111110011111011 |
3 | 1201201100100100121201001122 |
4 | 2333333333031333303323 |
5 | 3212133032331102324 |
6 | 44021144211335455 |
7 | 2531146516112126 |
oct | 277777715776373 |
9 | 51640310551048 |
10 | 13194126425339 |
11 | 4227663440362 |
12 | 159113a2b158b |
13 | 74927c175212 |
14 | 3388560073bd |
15 | 17d322147a5e |
hex | bffff37fcfb |
13194126425339 has 2 divisors, whose sum is σ = 13194126425340. Its totient is φ = 13194126425338.
The previous prime is 13194126425287. The next prime is 13194126425423. The reversal of 13194126425339 is 93352462149131.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (93352462149131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13194126425339 - 216 = 13194126359803 is a prime.
It is not a weakly prime, because it can be changed into another prime (13194126455339) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (37) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6597063212669 + 6597063212670.
It is an arithmetic number, because the mean of its divisors is an integer number (6597063212670).
Almost surely, 213194126425339 is an apocalyptic number.
13194126425339 is a deficient number, since it is larger than the sum of its proper divisors (1).
13194126425339 is an equidigital number, since it uses as much as digits as its factorization.
13194126425339 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4199040, while the sum is 53.
The spelling of 13194126425339 in words is "thirteen trillion, one hundred ninety-four billion, one hundred twenty-six million, four hundred twenty-five thousand, three hundred thirty-nine".
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