Base | Representation |
---|---|
bin | 1011111111111111111100… |
… | …1101111111110101001111 |
3 | 1201201100100100121201011202 |
4 | 2333333333031333311033 |
5 | 3212133032331103143 |
6 | 44021144211340115 |
7 | 2531146516112306 |
oct | 277777715776517 |
9 | 51640310551152 |
10 | 13194126425423 |
11 | 4227663440429 |
12 | 159113a2b163b |
13 | 74927c175278 |
14 | 33885600743d |
15 | 17d322147ab8 |
hex | bffff37fd4f |
13194126425423 has 2 divisors, whose sum is σ = 13194126425424. Its totient is φ = 13194126425422.
The previous prime is 13194126425339. The next prime is 13194126425429. The reversal of 13194126425423 is 32452462149131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13194126425423 - 242 = 8796079914319 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13194126425429) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6597063212711 + 6597063212712.
It is an arithmetic number, because the mean of its divisors is an integer number (6597063212712).
Almost surely, 213194126425423 is an apocalyptic number.
13194126425423 is a deficient number, since it is larger than the sum of its proper divisors (1).
13194126425423 is an equidigital number, since it uses as much as digits as its factorization.
13194126425423 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1244160, while the sum is 47.
The spelling of 13194126425423 in words is "thirteen trillion, one hundred ninety-four billion, one hundred twenty-six million, four hundred twenty-five thousand, four hundred twenty-three".
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