Base | Representation |
---|---|
bin | 1100000000010111010111… |
… | …0011110000110101000110 |
3 | 1201201221120100011101120210 |
4 | 3000011311303300311012 |
5 | 3212233420204113410 |
6 | 44024103551540250 |
7 | 2531461330131432 |
oct | 300056563606506 |
9 | 51657510141523 |
10 | 13200411004230 |
11 | 422a29897250a |
12 | 15923b2b2a686 |
13 | 749a4119c858 |
14 | 338c909339c2 |
15 | 17d58dc45220 |
hex | c0175cf0d46 |
13200411004230 has 32 divisors (see below), whose sum is σ = 31706150112000. Its totient is φ = 3517313634272.
The previous prime is 13200411004211. The next prime is 13200411004259. The reversal of 13200411004230 is 3240011400231.
It is a junction number, because it is equal to n+sod(n) for n = 13200411004197 and 13200411004206.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 174709530 + ... + 174785069.
It is an arithmetic number, because the mean of its divisors is an integer number (990817191000).
Almost surely, 213200411004230 is an apocalyptic number.
13200411004230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13200411004230 is an abundant number, since it is smaller than the sum of its proper divisors (18505739107770).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13200411004230 is a wasteful number, since it uses less digits than its factorization.
13200411004230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 349495868.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 13200411004230 its reverse (3240011400231), we get a palindrome (16440422404461).
The spelling of 13200411004230 in words is "thirteen trillion, two hundred billion, four hundred eleven million, four thousand, two hundred thirty".
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