Base | Representation |
---|---|
bin | 1100000000011001111110… |
… | …0111000000011000011010 |
3 | 1201202000101012210001211010 |
4 | 3000012133213000120122 |
5 | 3212241334222200010 |
6 | 44024301323114350 |
7 | 2531514604102563 |
oct | 300063747003032 |
9 | 51660335701733 |
10 | 13201112303130 |
11 | 422a618819784 |
12 | 15925699729b6 |
13 | 749b2357520b |
14 | 338d19b2916a |
15 | 17d5d05c2620 |
hex | c019f9c061a |
13201112303130 has 32 divisors (see below), whose sum is σ = 31721259927168. Its totient is φ = 3516008792000.
The previous prime is 13201112303051. The next prime is 13201112303149. The reversal of 13201112303130 is 3130321110231.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 13201112303097 and 13201112303106.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 267963846 + ... + 268013105.
It is an arithmetic number, because the mean of its divisors is an integer number (991289372724).
Almost surely, 213201112303130 is an apocalyptic number.
13201112303130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13201112303130 is an abundant number, since it is smaller than the sum of its proper divisors (18520147624038).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13201112303130 is a wasteful number, since it uses less digits than its factorization.
13201112303130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 535977782.
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 13201112303130 its reverse (3130321110231), we get a palindrome (16331433413361).
The spelling of 13201112303130 in words is "thirteen trillion, two hundred one billion, one hundred twelve million, three hundred three thousand, one hundred thirty".
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