13201441551050 has 48 divisors (see below), whose sum is σ = 25880666176440. Its totient is φ = 5002289859840.

The previous prime is 13201441551049. The next prime is 13201441551071. The reversal of 13201441551050 is 5015514410231.

13201441551050 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 12 ways, for example, as 13264359241 + 13188177191809 = 115171^2 + 3631553^2 .

It is a super-2 number, since 2×13201441551050² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13201441550998 and 13201441551016.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 85814117 + ... + 85967816.

Almost surely, 2^{13201441551050} is an apocalyptic number.

13201441551050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13201441551050 is a deficient number, since it is larger than the sum of its proper divisors (12679224625390).

13201441551050 is a wasteful number, since it uses less digits than its factorization.

13201441551050 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 171782027 (or 171782022 counting only the distinct ones).

The product of its (nonzero) digits is 12000, while the sum is 32.

Adding to 13201441551050 its reverse (5015514410231), we get a palindrome (18216955961281).

The spelling of 13201441551050 in words is "thirteen trillion, two hundred one billion, four hundred forty-one million, five hundred fifty-one thousand, fifty".