Base | Representation |
---|---|
bin | 11000100101110100… |
… | …00011111000000000 |
3 | 1021002002002210000010 |
4 | 30102322003320000 |
5 | 204014220041000 |
6 | 10022011024520 |
7 | 645106046310 |
oct | 142272037000 |
9 | 37062083003 |
10 | 13202112000 |
11 | 5665280170 |
12 | 268543b140 |
13 | 13252183bc |
14 | 8d353b440 |
15 | 524076d50 |
hex | 312e83e00 |
13202112000 has 1280 divisors, whose sum is σ = 58830520320. Its totient is φ = 2543616000.
The previous prime is 13202111983. The next prime is 13202112029. The reversal of 13202112000 is 21120231.
It is a tau number, because it is divible by the number of its divisors (1280).
It is a super-2 number, since 2×132021120002 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 280895977 + ... + 280896023.
It is an arithmetic number, because the mean of its divisors is an integer number (45961344).
Almost surely, 213202112000 is an apocalyptic number.
13202112000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13202112000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (29415260160).
13202112000 is an abundant number, since it is smaller than the sum of its proper divisors (45628408320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13202112000 is a wasteful number, since it uses less digits than its factorization.
13202112000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 120 (or 94 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 12.
Adding to 13202112000 its reverse (21120231), we get a palindrome (13223232231).
It can be divided in two parts, 1320 and 2112000, that multiplied together give a square (2787840000 = 528002).
The spelling of 13202112000 in words is "thirteen billion, two hundred two million, one hundred twelve thousand".
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