Base | Representation |
---|---|
bin | 1100000000011101101111… |
… | …0011001001111110101010 |
3 | 1201202002222120221010200210 |
4 | 3000013123303021332222 |
5 | 3212300421230334010 |
6 | 44024545435041550 |
7 | 2531551615314435 |
oct | 300073363117652 |
9 | 51662876833623 |
10 | 13202122121130 |
11 | 422aa96838a08 |
12 | 15927abba02b6 |
13 | 749c5483c167 |
14 | 338db3cb081c |
15 | 17d63e092b20 |
hex | c01dbcc9faa |
13202122121130 has 128 divisors (see below), whose sum is σ = 33679990294272. Its totient is φ = 3300535922688.
The previous prime is 13202122121093. The next prime is 13202122121137. The reversal of 13202122121130 is 3112122120231.
It is a junction number, because it is equal to n+sod(n) for n = 13202122121097 and 13202122121106.
It is not an unprimeable number, because it can be changed into a prime (13202122121137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 557580852 + ... + 557604528.
It is an arithmetic number, because the mean of its divisors is an integer number (263124924174).
Almost surely, 213202122121130 is an apocalyptic number.
13202122121130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 13202122121130, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16839995147136).
13202122121130 is an abundant number, since it is smaller than the sum of its proper divisors (20477868173142).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13202122121130 is a wasteful number, since it uses less digits than its factorization.
13202122121130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27928.
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 13202122121130 its reverse (3112122120231), we get a palindrome (16314244241361).
The spelling of 13202122121130 in words is "thirteen trillion, two hundred two billion, one hundred twenty-two million, one hundred twenty-one thousand, one hundred thirty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •