Base | Representation |
---|---|
bin | 1100000000011110001101… |
… | …1011110001111010111000 |
3 | 1201202010022111221202222001 |
4 | 3000013203123301322320 |
5 | 3212301202023223000 |
6 | 44025010252310344 |
7 | 2531555032131334 |
oct | 300074333617270 |
9 | 51663274852861 |
10 | 13202250211000 |
11 | 4230052075804 |
12 | 1592826a723b4 |
13 | 749c75239396 |
14 | 338dc6cd47c4 |
15 | 17d64a44546a |
hex | c01e36f1eb8 |
13202250211000 has 64 divisors (see below), whose sum is σ = 30957761952000. Its totient is φ = 5269875049600.
The previous prime is 13202250210991. The next prime is 13202250211019. The reversal of 13202250211000 is 11205220231.
13202250211000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13302055 + ... + 14260054.
It is an arithmetic number, because the mean of its divisors is an integer number (483715030500).
Almost surely, 213202250211000 is an apocalyptic number.
13202250211000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13202250211000 is an abundant number, since it is smaller than the sum of its proper divisors (17755511741000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13202250211000 is a wasteful number, since it uses less digits than its factorization.
13202250211000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27562609 (or 27562595 counting only the distinct ones).
The product of its (nonzero) digits is 240, while the sum is 19.
Adding to 13202250211000 its reverse (11205220231), we get a palindrome (13213455431231).
The spelling of 13202250211000 in words is "thirteen trillion, two hundred two billion, two hundred fifty million, two hundred eleven thousand".
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