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1320231331247 is a prime number
BaseRepresentation
bin10011001101100011111…
…010110110010110101111
311200012202012011120021212
4103031203322312112233
5133112313210044442
62450301135145035
7164245364104403
oct23154372662657
94605665146255
101320231331247
114699a8193864
12193a5297517b
13976606a926a
1447c8448b103
1524520138a82
hex13363eb65af

1320231331247 has 2 divisors, whose sum is σ = 1320231331248. Its totient is φ = 1320231331246.

The previous prime is 1320231331219. The next prime is 1320231331249. The reversal of 1320231331247 is 7421331320231.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1320231331247 is a prime.

Together with 1320231331249, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1320231331249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660115665623 + 660115665624.

It is an arithmetic number, because the mean of its divisors is an integer number (660115665624).

Almost surely, 21320231331247 is an apocalyptic number.

1320231331247 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320231331247 is an equidigital number, since it uses as much as digits as its factorization.

1320231331247 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18144, while the sum is 32.

Adding to 1320231331247 its reverse (7421331320231), we get a palindrome (8741562651478).

The spelling of 1320231331247 in words is "one trillion, three hundred twenty billion, two hundred thirty-one million, three hundred thirty-one thousand, two hundred forty-seven".