Base | Representation |
---|---|
bin | 1100000000011110100011… |
… | …0010110011010100100010 |
3 | 1201202010112210011020120021 |
4 | 3000013220302303110202 |
5 | 3212301343033212010 |
6 | 44025023223504054 |
7 | 2531560203345142 |
oct | 300075062632442 |
9 | 51663483136507 |
10 | 13202340132130 |
11 | 4230098902896 |
12 | 1592850bb802a |
13 | 749c8aa61456 |
14 | 338dd4c20922 |
15 | 17d6532a88da |
hex | c01e8cb3522 |
13202340132130 has 64 divisors (see below), whose sum is σ = 24365488912128. Its totient is φ = 5148609306880.
The previous prime is 13202340132101. The next prime is 13202340132131. The reversal of 13202340132130 is 3123104320231.
It is a junction number, because it is equal to n+sod(n) for n = 13202340132095 and 13202340132104.
It is not an unprimeable number, because it can be changed into a prime (13202340132131) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 177016107 + ... + 177090673.
It is an arithmetic number, because the mean of its divisors is an integer number (380710764252).
Almost surely, 213202340132130 is an apocalyptic number.
13202340132130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13202340132130 is a deficient number, since it is larger than the sum of its proper divisors (11163148779998).
13202340132130 is a wasteful number, since it uses less digits than its factorization.
13202340132130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 76731.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 13202340132130 its reverse (3123104320231), we get a palindrome (16325444452361).
The spelling of 13202340132130 in words is "thirteen trillion, two hundred two billion, three hundred forty million, one hundred thirty-two thousand, one hundred thirty".
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