1320243121997 has 2 divisors, whose sum is σ = 1320243121998. Its totient is φ = 1320243121996.

The previous prime is 1320243121991. The next prime is 1320243121999. The reversal of 1320243121997 is 7991213420231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 743951100676 + 576292021321 = 862526^2 + 759139^2 .

It is a cyclic number.

It is not a de Polignac number, because 1320243121997 - 2⁸ = 1320243121741 is a prime.

Together with 1320243121999, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1320243121991) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660121560998 + 660121560999.

It is an arithmetic number, because the mean of its divisors is an integer number (660121560999).

Almost surely, 2^{1320243121997} is an apocalyptic number.

It is an amenable number.

1320243121997 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320243121997 is an equidigital number, since it uses as much as digits as its factorization.

1320243121997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 163296, while the sum is 44.

The spelling of 1320243121997 in words is "one trillion, three hundred twenty billion, two hundred forty-three million, one hundred twenty-one thousand, nine hundred ninety-seven".