Base | Representation |
---|---|
bin | 10011001101100100100… |
… | …111110100111101001111 |
3 | 11200012210000100121011101 |
4 | 103031210213310331033 |
5 | 133112324214400444 |
6 | 2450302240003531 |
7 | 164245566242644 |
oct | 23154447647517 |
9 | 4605700317141 |
10 | 1320243121999 |
11 | 469a0390738a |
12 | 193a569005a7 |
13 | 97662c76c39 |
14 | 47c85c79dcb |
15 | 245211b73d4 |
hex | 133649f4f4f |
1320243121999 has 2 divisors, whose sum is σ = 1320243122000. Its totient is φ = 1320243121998.
The previous prime is 1320243121997. The next prime is 1320243122053. The reversal of 1320243121999 is 9991213420231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1320243121999 - 21 = 1320243121997 is a prime.
Together with 1320243121997, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1320243121991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660121560999 + 660121561000.
It is an arithmetic number, because the mean of its divisors is an integer number (660121561000).
Almost surely, 21320243121999 is an apocalyptic number.
1320243121999 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320243121999 is an equidigital number, since it uses as much as digits as its factorization.
1320243121999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 209952, while the sum is 46.
The spelling of 1320243121999 in words is "one trillion, three hundred twenty billion, two hundred forty-three million, one hundred twenty-one thousand, nine hundred ninety-nine".
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