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132031515244439 is a prime number
BaseRepresentation
bin11110000001010011111011…
…100100001011011110010111
3122022111002102022100102201102
4132001103323210023132113
5114301201020400310224
61144450235112020315
736544651013314616
oct3601237344133627
9568432368312642
10132031515244439
1139084284334678
121298471339169b
1358896980b0595
14248650640787d
15103e69920b4ae
hex7814fb90b797

132031515244439 has 2 divisors, whose sum is σ = 132031515244440. Its totient is φ = 132031515244438.

The previous prime is 132031515244381. The next prime is 132031515244463. The reversal of 132031515244439 is 934442515130231.

It is a strong prime.

It is an emirp because it is prime and its reverse (934442515130231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132031515244439 - 212 = 132031515240343 is a prime.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 132031515244393 and 132031515244402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132031515244339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66015757622219 + 66015757622220.

It is an arithmetic number, because the mean of its divisors is an integer number (66015757622220).

Almost surely, 2132031515244439 is an apocalyptic number.

132031515244439 is a deficient number, since it is larger than the sum of its proper divisors (1).

132031515244439 is an equidigital number, since it uses as much as digits as its factorization.

132031515244439 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1555200, while the sum is 47.

The spelling of 132031515244439 in words is "one hundred thirty-two trillion, thirty-one billion, five hundred fifteen million, two hundred forty-four thousand, four hundred thirty-nine".