Base | Representation |
---|---|
bin | 11110000001010011111011… |
… | …100100001011011110101111 |
3 | 122022111002102022100102202022 |
4 | 132001103323210023132233 |
5 | 114301201020400310323 |
6 | 1144450235112020355 |
7 | 36544651013314652 |
oct | 3601237344133657 |
9 | 568432368312668 |
10 | 132031515244463 |
11 | 3908428433469a |
12 | 129847133916bb |
13 | 58896980b05b3 |
14 | 2486506407899 |
15 | 103e69920b4c8 |
hex | 7814fb90b7af |
132031515244463 has 2 divisors, whose sum is σ = 132031515244464. Its totient is φ = 132031515244462.
The previous prime is 132031515244439. The next prime is 132031515244507. The reversal of 132031515244463 is 364442515130231.
It is an a-pointer prime, because the next prime (132031515244507) can be obtained adding 132031515244463 to its sum of digits (44).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132031515244463 - 236 = 131962795767727 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132031515244763) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66015757622231 + 66015757622232.
It is an arithmetic number, because the mean of its divisors is an integer number (66015757622232).
Almost surely, 2132031515244463 is an apocalyptic number.
132031515244463 is a deficient number, since it is larger than the sum of its proper divisors (1).
132031515244463 is an equidigital number, since it uses as much as digits as its factorization.
132031515244463 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1036800, while the sum is 44.
The spelling of 132031515244463 in words is "one hundred thirty-two trillion, thirty-one billion, five hundred fifteen million, two hundred forty-four thousand, four hundred sixty-three".
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