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132034430230 = 2517776673119
BaseRepresentation
bin111101011110111011…
…1011000010100010110
3110121210201002000020121
41322331313120110112
54130401303231410
6140353352022154
712352636065553
oct1727567302426
9417721060217
10132034430230
1150aa4aa272a
122170a09195a
13c5b25154c1
146567767a2a
15367b7779da
hex1ebddd8516

132034430230 has 16 divisors (see below), whose sum is σ = 251642090880. Its totient is φ = 49707079552.

The previous prime is 132034430167. The next prime is 132034430233. The reversal of 132034430230 is 32034430231.

It is a junction number, because it is equal to n+sod(n) for n = 132034430195 and 132034430204.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132034430233) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 388336390 + ... + 388336729.

It is an arithmetic number, because the mean of its divisors is an integer number (15727630680).

Almost surely, 2132034430230 is an apocalyptic number.

132034430230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

132034430230 is a deficient number, since it is larger than the sum of its proper divisors (119607660650).

132034430230 is a wasteful number, since it uses less digits than its factorization.

132034430230 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 776673143.

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 132034430230 its reverse (32034430231), we get a palindrome (164068860461).

Subtracting from 132034430230 its reverse (32034430231), we obtain a palindrome (99999999999).

The spelling of 132034430230 in words is "one hundred thirty-two billion, thirty-four million, four hundred thirty thousand, two hundred thirty".

Divisors: 1 2 5 10 17 34 85 170 776673119 1553346238 3883365595 7766731190 13203443023 26406886046 66017215115 132034430230