Base | Representation |
---|---|
bin | 1100000000101001101111… |
… | …1010101010010011111000 |
3 | 1201202102022012221022010222 |
4 | 3000022123322222103320 |
5 | 3212324021400022130 |
6 | 44030241335155212 |
7 | 2532024524102345 |
oct | 300123372522370 |
9 | 51672265838128 |
10 | 13205345314040 |
11 | 42313a0192500 |
12 | 159334b515b08 |
13 | 74a34953b4b9 |
14 | 3391dbdb57cc |
15 | 17d77c022ce5 |
hex | c029beaa4f8 |
13205345314040 has 96 divisors (see below), whose sum is σ = 32659965450000. Its totient is φ = 4801753904640.
The previous prime is 13205345314039. The next prime is 13205345314163. The reversal of 13205345314040 is 4041354350231.
It is a super-2 number, since 2×132053453140402 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 195981476 + ... + 196048844.
Almost surely, 213205345314040 is an apocalyptic number.
13205345314040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13205345314040 is an abundant number, since it is smaller than the sum of its proper divisors (19454620135960).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13205345314040 is a wasteful number, since it uses less digits than its factorization.
13205345314040 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 107901 (or 107886 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 13205345314040 its reverse (4041354350231), we get a palindrome (17246699664271).
The spelling of 13205345314040 in words is "thirteen trillion, two hundred five billion, three hundred forty-five million, three hundred fourteen thousand, forty".
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