132104412400240 has 40 divisors (see below), whose sum is σ = 351020295807840. Its totient is φ = 45292941394176.

The previous prime is 132104412400193. The next prime is 132104412400277. The reversal of 132104412400240 is 42004214401231.

It is a tau number, because it is divible by the number of its divisors (40).

It is a super-2 number, since 2×132104412400240² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (28).

It is a junction number, because it is equal to n+sod(n) for n = 132104412400199 and 132104412400208.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 117950367655 + ... + 117950368774.

It is an arithmetic number, because the mean of its divisors is an integer number (8775507395196).

Almost surely, 2^{132104412400240} is an apocalyptic number.

132104412400240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

132104412400240 is an abundant number, since it is smaller than the sum of its proper divisors (218915883407600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132104412400240 is a wasteful number, since it uses less digits than its factorization.

132104412400240 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 235900736449 (or 235900736443 counting only the distinct ones).

The product of its (nonzero) digits is 6144, while the sum is 28.

Adding to 132104412400240 its reverse (42004214401231), we get a palindrome (174108626801471).

The spelling of 132104412400240 in words is "one hundred thirty-two trillion, one hundred four billion, four hundred twelve million, four hundred thousand, two hundred forty".