Base | Representation |
---|---|
bin | 111101100001001101… |
… | …1111001010010001111 |
3 | 110122000001100210220122 |
4 | 1323002123321102033 |
5 | 4131030421030221 |
6 | 140405131335155 |
7 | 12354556626554 |
oct | 1730233712217 |
9 | 418001323818 |
10 | 132111111311 |
11 | 51034307323 |
12 | 2172b8b14bb |
13 | c5c538301a |
14 | 6573a08a2b |
15 | 3683372eab |
hex | 1ec26f948f |
132111111311 has 2 divisors, whose sum is σ = 132111111312. Its totient is φ = 132111111310.
The previous prime is 132111111287. The next prime is 132111111313. The reversal of 132111111311 is 113111111231.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132111111311 - 26 = 132111111247 is a prime.
Together with 132111111313, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 132111111311.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132111111313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66055555655 + 66055555656.
It is an arithmetic number, because the mean of its divisors is an integer number (66055555656).
Almost surely, 2132111111311 is an apocalyptic number.
132111111311 is a deficient number, since it is larger than the sum of its proper divisors (1).
132111111311 is an equidigital number, since it uses as much as digits as its factorization.
132111111311 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 18, while the sum is 17.
Adding to 132111111311 its reverse (113111111231), we get a palindrome (245222222542).
The spelling of 132111111311 in words is "one hundred thirty-two billion, one hundred eleven million, one hundred eleven thousand, three hundred eleven".
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