Base | Representation |
---|---|
bin | 111101100001001111… |
… | …1101010101111100000 |
3 | 110122000010020001120121 |
4 | 1323002133222233200 |
5 | 4131031144202240 |
6 | 140405204450024 |
7 | 12354601216144 |
oct | 1730237525740 |
9 | 418003201517 |
10 | 132112100320 |
11 | 51034922392 |
12 | 217300a9914 |
13 | c5c563b235 |
14 | 6573bc5224 |
15 | 36834bb04a |
hex | 1ec27eabe0 |
132112100320 has 24 divisors (see below), whose sum is σ = 312114837384. Its totient is φ = 52844840064.
The previous prime is 132112100311. The next prime is 132112100339. The reversal of 132112100320 is 23001211231.
It is a Harshad number since it is a multiple of its sum of digits (16).
It is a junction number, because it is equal to n+sod(n) for n = 132112100294 and 132112100303.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 412850154 + ... + 412850473.
It is an arithmetic number, because the mean of its divisors is an integer number (13004784891).
Almost surely, 2132112100320 is an apocalyptic number.
132112100320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132112100320 is an abundant number, since it is smaller than the sum of its proper divisors (180002737064).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132112100320 is an equidigital number, since it uses as much as digits as its factorization.
132112100320 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 825700642 (or 825700634 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 132112100320 its reverse (23001211231), we get a palindrome (155113311551).
The spelling of 132112100320 in words is "one hundred thirty-two billion, one hundred twelve million, one hundred thousand, three hundred twenty".
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