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13212043310400 = 2635211316379111
BaseRepresentation
bin1100000001000010101100…
…1001011111010101000000
31201210001121000101202211020
43000100223021133111000
53212431231041413100
644033310124345440
72532352515115464
oct300205311372500
951701530352736
1013212043310400
114234218014290
1215946ba6a5280
1374ab760c465c
1433967579a4a4
1517da200845a0
hexc042b25f540

13212043310400 has 336 divisors, whose sum is σ = 47302652103168. Its totient is φ = 3201866496000.

The previous prime is 13212043310383. The next prime is 13212043310413. The reversal of 13212043310400 is 401334021231.

It is a happy number.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 166966845 + ... + 167045955.

It is an arithmetic number, because the mean of its divisors is an integer number (140781702688).

Almost surely, 213212043310400 is an apocalyptic number.

13212043310400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13212043310400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (23651326051584).

13212043310400 is an abundant number, since it is smaller than the sum of its proper divisors (34090608792768).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13212043310400 is a wasteful number, since it uses less digits than its factorization.

13212043310400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 82310 (or 82295 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 13212043310400 its reverse (401334021231), we get a palindrome (13613377331631).

The spelling of 13212043310400 in words is "thirteen trillion, two hundred twelve billion, forty-three million, three hundred ten thousand, four hundred".