Base | Representation |
---|---|
bin | 1100000001000011000100… |
… | …0110111011101110000000 |
3 | 1201210001211222112221122022 |
4 | 3000100301012323232000 |
5 | 3212431432141203202 |
6 | 44033324055501012 |
7 | 2532355141051634 |
oct | 300206106735600 |
9 | 51701758487568 |
10 | 13212143303552 |
11 | 4234269500656 |
12 | 1594728087768 |
13 | 74ab90a34cbb |
14 | 339684b88dc4 |
15 | 17da28c36ea2 |
hex | c04311bbb80 |
13212143303552 has 32 divisors (see below), whose sum is σ = 26322902197200. Its totient is φ = 6605610987520.
The previous prime is 13212143303549. The next prime is 13212143303617. The reversal of 13212143303552 is 25530334121231.
It is a tau number, because it is divible by the number of its divisors (32).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1752524 + ... + 5430987.
Almost surely, 213212143303552 is an apocalyptic number.
It is an amenable number.
13212143303552 is a deficient number, since it is larger than the sum of its proper divisors (13110758893648).
13212143303552 is an equidigital number, since it uses as much as digits as its factorization.
13212143303552 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7197894 (or 7197882 counting only the distinct ones).
The product of its (nonzero) digits is 64800, while the sum is 35.
Adding to 13212143303552 its reverse (25530334121231), we get a palindrome (38742477424783).
The spelling of 13212143303552 in words is "thirteen trillion, two hundred twelve billion, one hundred forty-three million, three hundred three thousand, five hundred fifty-two".
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