Base | Representation |
---|---|
bin | 1100000001000011101001… |
… | …1100110101101111000000 |
3 | 1201210002020220111001012121 |
4 | 3000100322130311233000 |
5 | 3212432242302304102 |
6 | 44033351415134024 |
7 | 2532362053232602 |
oct | 300207234655700 |
9 | 51702226431177 |
10 | 13212300041152 |
11 | 4234339a24963 |
12 | 1594770674314 |
13 | 74abb7352844 |
14 | 33969b909172 |
15 | 17da37897b37 |
hex | c043a735bc0 |
13212300041152 has 28 divisors (see below), whose sum is σ = 26218301417496. Its totient is φ = 6606113857280.
The previous prime is 13212300041141. The next prime is 13212300041191. The reversal of 13212300041152 is 25114000321231.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14214027 + ... + 15114997.
Almost surely, 213212300041152 is an apocalyptic number.
It is an amenable number.
13212300041152 is a deficient number, since it is larger than the sum of its proper divisors (13006001376344).
13212300041152 is an equidigital number, since it uses as much as digits as its factorization.
13212300041152 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1130116 (or 1130106 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 13212300041152 its reverse (25114000321231), we get a palindrome (38326300362383).
The spelling of 13212300041152 in words is "thirteen trillion, two hundred twelve billion, three hundred million, forty-one thousand, one hundred fifty-two".
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