Base | Representation |
---|---|
bin | 11110000010101001100010… |
… | …010100000111110010011100 |
3 | 122022210212200020120121122212 |
4 | 132002221202110013302130 |
5 | 114304202242422322000 |
6 | 1145000400053055552 |
7 | 36554413563623042 |
oct | 3602514224076234 |
9 | 568725606517585 |
10 | 132123433401500 |
11 | 3910a262782532 |
12 | 1299a4a66275b8 |
13 | 5895256422a28 |
14 | 248ab45d78392 |
15 | 1041c78b80c35 |
hex | 782a62507c9c |
132123433401500 has 48 divisors (see below), whose sum is σ = 288560647895520. Its totient is φ = 52848811209600.
The previous prime is 132123433401431. The next prime is 132123433401523. The reversal of 132123433401500 is 5104334321231.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 47336816 + ... + 50050184.
It is an arithmetic number, because the mean of its divisors is an integer number (6011680164490).
Almost surely, 2132123433401500 is an apocalyptic number.
132123433401500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132123433401500 is an abundant number, since it is smaller than the sum of its proper divisors (156437214494020).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132123433401500 is a wasteful number, since it uses less digits than its factorization.
132123433401500 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2810775 (or 2810763 counting only the distinct ones).
The product of its (nonzero) digits is 25920, while the sum is 32.
Adding to 132123433401500 its reverse (5104334321231), we get a palindrome (137227767722731).
The spelling of 132123433401500 in words is "one hundred thirty-two trillion, one hundred twenty-three billion, four hundred thirty-three million, four hundred one thousand, five hundred".
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