Base | Representation |
---|---|
bin | 11110000010101010010110… |
… | …110100011111101010100100 |
3 | 122022210221221122011001112112 |
4 | 132002222112310133222210 |
5 | 114304211043430200030 |
6 | 1145001023321540152 |
7 | 36554444451306305 |
oct | 3602522664375244 |
9 | 568727848131475 |
10 | 132124314303140 |
11 | 3910a674a4aa15 |
12 | 1299a6b1644658 |
13 | 5895366a904c3 |
14 | 248abcad627ac |
15 | 1041ccb188a95 |
hex | 782a96d1faa4 |
132124314303140 has 96 divisors (see below), whose sum is σ = 303303967561728. Its totient is φ = 48129258240000.
The previous prime is 132124314303133. The next prime is 132124314303143. The reversal of 132124314303140 is 41303413421231.
It is a junction number, because it is equal to n+sod(n) for n = 132124314303097 and 132124314303106.
It is not an unprimeable number, because it can be changed into a prime (132124314303143) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 70654190 + ... + 72500090.
It is an arithmetic number, because the mean of its divisors is an integer number (3159416328768).
Almost surely, 2132124314303140 is an apocalyptic number.
132124314303140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 132124314303140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (151651983780864).
132124314303140 is an abundant number, since it is smaller than the sum of its proper divisors (171179653258588).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132124314303140 is a wasteful number, since it uses less digits than its factorization.
132124314303140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1852749 (or 1852747 counting only the distinct ones).
The product of its (nonzero) digits is 20736, while the sum is 32.
Adding to 132124314303140 its reverse (41303413421231), we get a palindrome (173427727724371).
The spelling of 132124314303140 in words is "one hundred thirty-two trillion, one hundred twenty-four billion, three hundred fourteen million, three hundred three thousand, one hundred forty".
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