Base | Representation |
---|---|
bin | 11110000010101111101111… |
… | …110010111010111101111111 |
3 | 122022211111212222210001111021 |
4 | 132002233233302322331333 |
5 | 114304304422104431312 |
6 | 1145003421513005011 |
7 | 36555041050213201 |
oct | 3602575762727577 |
9 | 568744788701437 |
10 | 132130102030207 |
11 | 39112074a75a26 |
12 | 1299b8479b3767 |
13 | 5895a79b95988 |
14 | 248b1b98b6771 |
15 | 1042019340c07 |
hex | 782befcbaf7f |
132130102030207 has 2 divisors, whose sum is σ = 132130102030208. Its totient is φ = 132130102030206.
The previous prime is 132130102030181. The next prime is 132130102030229. The reversal of 132130102030207 is 702030201031231.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (702030201031231) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132130102030207 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132130102030237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66065051015103 + 66065051015104.
It is an arithmetic number, because the mean of its divisors is an integer number (66065051015104).
Almost surely, 2132130102030207 is an apocalyptic number.
132130102030207 is a deficient number, since it is larger than the sum of its proper divisors (1).
132130102030207 is an equidigital number, since it uses as much as digits as its factorization.
132130102030207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 132130102030207 its reverse (702030201031231), we get a palindrome (834160303061438).
The spelling of 132130102030207 in words is "one hundred thirty-two trillion, one hundred thirty billion, one hundred two million, thirty thousand, two hundred seven".
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