Base | Representation |
---|---|
bin | 1100000001000111001101… |
… | …0111110100000110100111 |
3 | 1201210011201110110020212002 |
4 | 3000101303113310012213 |
5 | 3212441221241300223 |
6 | 44034030251515515 |
7 | 2532424530404342 |
oct | 300216327640647 |
9 | 51704643406762 |
10 | 13213255025063 |
11 | 4234789aa1465 |
12 | 1594998458b9b |
13 | 74b00a15ac92 |
14 | 33974c699459 |
15 | 17da91635e28 |
hex | c04735f41a7 |
13213255025063 has 2 divisors, whose sum is σ = 13213255025064. Its totient is φ = 13213255025062.
The previous prime is 13213255025053. The next prime is 13213255025101. The reversal of 13213255025063 is 36052055231231.
It is an a-pointer prime, because the next prime (13213255025101) can be obtained adding 13213255025063 to its sum of digits (38).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13213255025063 - 230 = 13212181283239 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13213255025053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6606627512531 + 6606627512532.
It is an arithmetic number, because the mean of its divisors is an integer number (6606627512532).
Almost surely, 213213255025063 is an apocalyptic number.
13213255025063 is a deficient number, since it is larger than the sum of its proper divisors (1).
13213255025063 is an equidigital number, since it uses as much as digits as its factorization.
13213255025063 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162000, while the sum is 38.
The spelling of 13213255025063 in words is "thirteen trillion, two hundred thirteen billion, two hundred fifty-five million, twenty-five thousand, sixty-three".
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