Base | Representation |
---|---|
bin | 1100000001000111011010… |
… | …1110100110101110011110 |
3 | 1201210011212101101220101200 |
4 | 3000101312232212232132 |
5 | 3212441330200044410 |
6 | 44034040022420330 |
7 | 2532426113115303 |
oct | 300216656465636 |
9 | 51704771356350 |
10 | 13213311331230 |
11 | 423480885a08a |
12 | 15949b32916a6 |
13 | 74b018a1383a |
14 | 339755d550aa |
15 | 17da965593c0 |
hex | c0476ba6b9e |
13213311331230 has 48 divisors (see below), whose sum is σ = 35848288139040. Its totient is φ = 3370351875264.
The previous prime is 13213311331201. The next prime is 13213311331267. The reversal of 13213311331230 is 3213311331231.
13213311331230 is a `hidden beast` number, since 1 + 3 + 2 + 1 + 3 + 311 + 3 + 312 + 30 = 666.
It is a super-2 number, since 2×132133113312302 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13213311331194 and 13213311331203.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3191619025 + ... + 3191623164.
It is an arithmetic number, because the mean of its divisors is an integer number (746839336230).
Almost surely, 213213311331230 is an apocalyptic number.
13213311331230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13213311331230 is an abundant number, since it is smaller than the sum of its proper divisors (22634976807810).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13213311331230 is a wasteful number, since it uses less digits than its factorization.
13213311331230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6383242225 (or 6383242222 counting only the distinct ones).
The product of its (nonzero) digits is 2916, while the sum is 27.
Adding to 13213311331230 its reverse (3213311331231), we get a palindrome (16426622662461).
Subtracting from 13213311331230 its reverse (3213311331231), we obtain a palindrome (9999999999999).
The spelling of 13213311331230 in words is "thirteen trillion, two hundred thirteen billion, three hundred eleven million, three hundred thirty-one thousand, two hundred thirty".
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