Base | Representation |
---|---|
bin | 10011001110101001110… |
… | …101110011111000101110 |
3 | 11200022202221112102102001 |
4 | 103032221311303320232 |
5 | 133122214012244114 |
6 | 2451013402322514 |
7 | 164316430131250 |
oct | 23165165637056 |
9 | 4608687472361 |
10 | 1321404415534 |
11 | 46a44a386405 |
12 | 19411b7b943a |
13 | 977b9738588 |
14 | 47d561b1cd0 |
15 | 2458d109374 |
hex | 133a9d73e2e |
1321404415534 has 32 divisors (see below), whose sum is σ = 2398627650240. Its totient is φ = 532978556928.
The previous prime is 1321404415511. The next prime is 1321404415601. The reversal of 1321404415534 is 4355144041231.
It is a happy number.
It is a super-2 number, since 2×13214044155342 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1321404415493 and 1321404415502.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5483862 + ... + 5719750.
It is an arithmetic number, because the mean of its divisors is an integer number (74957114070).
Almost surely, 21321404415534 is an apocalyptic number.
1321404415534 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
1321404415534 is a deficient number, since it is larger than the sum of its proper divisors (1077223234706).
1321404415534 is a wasteful number, since it uses less digits than its factorization.
1321404415534 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 259452.
The product of its (nonzero) digits is 115200, while the sum is 37.
Adding to 1321404415534 its reverse (4355144041231), we get a palindrome (5676548456765).
The spelling of 1321404415534 in words is "one trillion, three hundred twenty-one billion, four hundred four million, four hundred fifteen thousand, five hundred thirty-four".
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