Base | Representation |
---|---|
bin | 11000100111010110… |
… | …01110011011111111 |
3 | 1021002222100120110021 |
4 | 30103223032123333 |
5 | 204031020002234 |
6 | 10023151153011 |
7 | 645323435503 |
oct | 142353163377 |
9 | 37088316407 |
10 | 13215000319 |
11 | 5671583374 |
12 | 2689815767 |
13 | 1327aab821 |
14 | 8d5134303 |
15 | 5252709b4 |
hex | 313ace6ff |
13215000319 has 2 divisors, whose sum is σ = 13215000320. Its totient is φ = 13215000318.
The previous prime is 13215000317. The next prime is 13215000329. The reversal of 13215000319 is 91300051231.
It is a weak prime.
It is an emirp because it is prime and its reverse (91300051231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13215000319 - 21 = 13215000317 is a prime.
It is a super-2 number, since 2×132150003192 (a number of 21 digits) contains 22 as substring.
Together with 13215000317, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 13215000293 and 13215000302.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13215000317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6607500159 + 6607500160.
It is an arithmetic number, because the mean of its divisors is an integer number (6607500160).
Almost surely, 213215000319 is an apocalyptic number.
13215000319 is a deficient number, since it is larger than the sum of its proper divisors (1).
13215000319 is an equidigital number, since it uses as much as digits as its factorization.
13215000319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 810, while the sum is 25.
The spelling of 13215000319 in words is "thirteen billion, two hundred fifteen million, three hundred nineteen", and thus it is an aban number.
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