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132174655397 is a prime number
BaseRepresentation
bin111101100011000111…
…0010010111110100101
3110122011110221012000022
41323012032102332211
54131143202433042
6140415321324525
712356261014361
oct1730616227645
9418143835008
10132174655397
11510671689a4
1221749036745
13c6055a1185
14657c22a2a1
153688c25cd2
hex1ec6392fa5

132174655397 has 2 divisors, whose sum is σ = 132174655398. Its totient is φ = 132174655396.

The previous prime is 132174655351. The next prime is 132174655399. The reversal of 132174655397 is 793556471231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 102711276196 + 29463379201 = 320486^2 + 171649^2 .

It is an emirp because it is prime and its reverse (793556471231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132174655397 - 216 = 132174589861 is a prime.

Together with 132174655399, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132174655399) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66087327698 + 66087327699.

It is an arithmetic number, because the mean of its divisors is an integer number (66087327699).

Almost surely, 2132174655397 is an apocalyptic number.

It is an amenable number.

132174655397 is a deficient number, since it is larger than the sum of its proper divisors (1).

132174655397 is an equidigital number, since it uses as much as digits as its factorization.

132174655397 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4762800, while the sum is 53.

The spelling of 132174655397 in words is "one hundred thirty-two billion, one hundred seventy-four million, six hundred fifty-five thousand, three hundred ninety-seven".