Base | Representation |
---|---|
bin | 111101100100001100… |
… | …1000001010111110100 |
3 | 110122021000100202122121 |
4 | 1323020121001113310 |
5 | 4131232010140200 |
6 | 140423101005324 |
7 | 12360212065411 |
oct | 1731031012764 |
9 | 418230322577 |
10 | 132211021300 |
11 | 51085747166 |
12 | 21759253844 |
13 | c60cc94867 |
14 | 6582db5108 |
15 | 368c00ae1a |
hex | 1ec86415f4 |
132211021300 has 72 divisors (see below), whose sum is σ = 305365455360. Its totient is φ = 49512844800.
The previous prime is 132211021213. The next prime is 132211021303. The reversal of 132211021300 is 3120112231.
132211021300 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132211021303) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 121111 + ... + 528289.
It is an arithmetic number, because the mean of its divisors is an integer number (4241186880).
Almost surely, 2132211021300 is an apocalyptic number.
132211021300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 132211021300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (152682727680).
132211021300 is an abundant number, since it is smaller than the sum of its proper divisors (173154434060).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132211021300 is a wasteful number, since it uses less digits than its factorization.
132211021300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 407401 (or 407394 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 132211021300 its reverse (3120112231), we get a palindrome (135331133531).
The spelling of 132211021300 in words is "one hundred thirty-two billion, two hundred eleven million, twenty-one thousand, three hundred".
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