Search a number
-
+
132213031344140 = 22519347929029853
BaseRepresentation
bin11110000011111100111110…
…110001001001100000001100
3122100010102221110220200202212
4132003330332301021200030
5114312134242011003030
61145105454512005552
736564035111565515
oct3603747661114014
9570112843820685
10132213031344140
1139144260452a0a
12129b39308308b8
1358a0834b63136
1424912056d7a0c
15104426ea8e595
hex783f3ec4980c

132213031344140 has 24 divisors (see below), whose sum is σ = 292260385077360. Its totient is φ = 50101780298688.

The previous prime is 132213031344139. The next prime is 132213031344169. The reversal of 132213031344140 is 41443130312231.

It is a super-3 number, since 3×1322130313441403 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 132213031344097 and 132213031344106.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 173964514547 + ... + 173964515306.

It is an arithmetic number, because the mean of its divisors is an integer number (12177516044890).

Almost surely, 2132213031344140 is an apocalyptic number.

132213031344140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

132213031344140 is an abundant number, since it is smaller than the sum of its proper divisors (160047353733220).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132213031344140 is a wasteful number, since it uses less digits than its factorization.

132213031344140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 347929029881 (or 347929029879 counting only the distinct ones).

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 132213031344140 its reverse (41443130312231), we get a palindrome (173656161656371).

The spelling of 132213031344140 in words is "one hundred thirty-two trillion, two hundred thirteen billion, thirty-one million, three hundred forty-four thousand, one hundred forty".

Divisors: 1 2 4 5 10 19 20 38 76 95 190 380 347929029853 695858059706 1391716119412 1739645149265 3479290298530 6610651567207 6958580597060 13221303134414 26442606268828 33053257836035 66106515672070 132213031344140