Base | Representation |
---|---|
bin | 1100000001101000111101… |
… | …0001101111110001011100 |
3 | 1201211001002201212201100212 |
4 | 3000122033101233301130 |
5 | 3213113244130143400 |
6 | 44042125150311552 |
7 | 2533165150133633 |
oct | 300321721576134 |
9 | 51731081781325 |
10 | 13222313131100 |
11 | 423860806a607 |
12 | 15966a5ab85b8 |
13 | 74bb21974138 |
14 | 339d6b6b851a |
15 | 17de2198e335 |
hex | c068f46fc5c |
13222313131100 has 72 divisors (see below), whose sum is σ = 29513710168320. Its totient is φ = 5139154422720.
The previous prime is 13222313131087. The next prime is 13222313131109. The reversal of 13222313131100 is 113131322231.
13222313131100 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13222313131109) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 9466334 + ... + 10772933.
Almost surely, 213222313131100 is an apocalyptic number.
13222313131100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13222313131100 is an abundant number, since it is smaller than the sum of its proper divisors (16291397037220).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13222313131100 is a wasteful number, since it uses less digits than its factorization.
13222313131100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20239467 (or 20239460 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 13222313131100 its reverse (113131322231), we get a palindrome (13335444453331).
The spelling of 13222313131100 in words is "thirteen trillion, two hundred twenty-two billion, three hundred thirteen million, one hundred thirty-one thousand, one hundred".
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