Base | Representation |
---|---|
bin | 1100000001101011101000… |
… | …1100001101101010001111 |
3 | 1201211002221220121222022121 |
4 | 3000122322030031222033 |
5 | 3213121232433212233 |
6 | 44042324425553411 |
7 | 2533222041600241 |
oct | 300327214155217 |
9 | 51732856558277 |
10 | 13223033100943 |
11 | 4238947509606 |
12 | 1596867045867 |
13 | 74bc07b85cb3 |
14 | 339dd9170091 |
15 | 17de64ca892d |
hex | c06ba30da8f |
13223033100943 has 2 divisors, whose sum is σ = 13223033100944. Its totient is φ = 13223033100942.
The previous prime is 13223033100941. The next prime is 13223033101013. The reversal of 13223033100943 is 34900133032231.
It is a weak prime.
It is an emirp because it is prime and its reverse (34900133032231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13223033100943 - 21 = 13223033100941 is a prime.
Together with 13223033100941, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 13223033100899 and 13223033100908.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13223033100941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6611516550471 + 6611516550472.
It is an arithmetic number, because the mean of its divisors is an integer number (6611516550472).
Almost surely, 213223033100943 is an apocalyptic number.
13223033100943 is a deficient number, since it is larger than the sum of its proper divisors (1).
13223033100943 is an equidigital number, since it uses as much as digits as its factorization.
13223033100943 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 34992, while the sum is 34.
The spelling of 13223033100943 in words is "thirteen trillion, two hundred twenty-three billion, thirty-three million, one hundred thousand, nine hundred forty-three".
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