Base | Representation |
---|---|
bin | 111101100101000111… |
… | …1101000011110001001 |
3 | 110122100011212110102102 |
4 | 1323022033220132021 |
5 | 4131312440130231 |
6 | 140430131243145 |
7 | 12361040266103 |
oct | 1731217503611 |
9 | 418304773372 |
10 | 132242114441 |
11 | 510a1253978 |
12 | 217677494b5 |
13 | c616560278 |
14 | 658718a573 |
15 | 368eaedacb |
hex | 1eca3e8789 |
132242114441 has 2 divisors, whose sum is σ = 132242114442. Its totient is φ = 132242114440.
The previous prime is 132242114401. The next prime is 132242114443. The reversal of 132242114441 is 144411242231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 98900815225 + 33341299216 = 314485^2 + 182596^2 .
It is an emirp because it is prime and its reverse (144411242231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132242114441 - 210 = 132242113417 is a prime.
Together with 132242114443, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (132242114443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66121057220 + 66121057221.
It is an arithmetic number, because the mean of its divisors is an integer number (66121057221).
Almost surely, 2132242114441 is an apocalyptic number.
It is an amenable number.
132242114441 is a deficient number, since it is larger than the sum of its proper divisors (1).
132242114441 is an equidigital number, since it uses as much as digits as its factorization.
132242114441 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6144, while the sum is 29.
Adding to 132242114441 its reverse (144411242231), we get a palindrome (276653356672).
The spelling of 132242114441 in words is "one hundred thirty-two billion, two hundred forty-two million, one hundred fourteen thousand, four hundred forty-one".
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