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132242114441 is a prime number
BaseRepresentation
bin111101100101000111…
…1101000011110001001
3110122100011212110102102
41323022033220132021
54131312440130231
6140430131243145
712361040266103
oct1731217503611
9418304773372
10132242114441
11510a1253978
12217677494b5
13c616560278
14658718a573
15368eaedacb
hex1eca3e8789

132242114441 has 2 divisors, whose sum is σ = 132242114442. Its totient is φ = 132242114440.

The previous prime is 132242114401. The next prime is 132242114443. The reversal of 132242114441 is 144411242231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98900815225 + 33341299216 = 314485^2 + 182596^2 .

It is an emirp because it is prime and its reverse (144411242231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132242114441 - 210 = 132242113417 is a prime.

Together with 132242114443, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (132242114443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66121057220 + 66121057221.

It is an arithmetic number, because the mean of its divisors is an integer number (66121057221).

Almost surely, 2132242114441 is an apocalyptic number.

It is an amenable number.

132242114441 is a deficient number, since it is larger than the sum of its proper divisors (1).

132242114441 is an equidigital number, since it uses as much as digits as its factorization.

132242114441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6144, while the sum is 29.

Adding to 132242114441 its reverse (144411242231), we get a palindrome (276653356672).

The spelling of 132242114441 in words is "one hundred thirty-two billion, two hundred forty-two million, one hundred fourteen thousand, four hundred forty-one".