144411242231 has 2 divisors, whose sum is σ = 144411242232. Its totient is φ = 144411242230.

The previous prime is 144411242219. The next prime is 144411242233. The reversal of 144411242231 is 132242114441.

It is a strong prime.

It is an emirp because it is prime and its reverse (132242114441) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-144411242231 is a prime.

It is a super-2 number, since 2×144411242231² (a number of 23 digits) contains 22 as substring.

Together with 144411242233, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 144411242194 and 144411242203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (144411242233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72205621115 + 72205621116.

It is an arithmetic number, because the mean of its divisors is an integer number (72205621116).

Almost surely, 2^144411242231 is an apocalyptic number.

144411242231 is a deficient number, since it is larger than the sum of its proper divisors (1).

144411242231 is an equidigital number, since it uses as much as digits as its factorization.

144411242231 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6144, while the sum is 29.

Adding to 144411242231 its reverse (132242114441), we get a palindrome (276653356672).

The spelling of 144411242231 in words is "one hundred forty-four billion, four hundred eleven million, two hundred forty-two thousand, two hundred thirty-one".