Base | Representation |
---|---|
bin | 11110000100101010100101… |
… | …101110101110000101011010 |
3 | 122100022010100102110221120102 |
4 | 132010222211232232011122 |
5 | 114313440040332313200 |
6 | 1145144154153055402 |
7 | 36600420512316605 |
oct | 3604524556560532 |
9 | 570263312427512 |
10 | 132262003401050 |
11 | 39163000947116 |
12 | 12a013193b7562 |
13 | 58a533a960cc3 |
14 | 249372d6c533c |
15 | 10456890836d5 |
hex | 784aa5bae15a |
132262003401050 has 24 divisors (see below), whose sum is σ = 246012373340256. Its totient is φ = 52903715981040.
The previous prime is 132262003401037. The next prime is 132262003401107. The reversal of 132262003401050 is 50104300262231.
It is a happy number.
It is a super-2 number, since 2×1322620034010502 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 24670742 + ... + 29549441.
It is an arithmetic number, because the mean of its divisors is an integer number (10250515555844).
Almost surely, 2132262003401050 is an apocalyptic number.
132262003401050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132262003401050 is a deficient number, since it is larger than the sum of its proper divisors (113750369939206).
132262003401050 is a wasteful number, since it uses less digits than its factorization.
132262003401050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54268982 (or 54268977 counting only the distinct ones).
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 132262003401050 its reverse (50104300262231), we get a palindrome (182366303663281).
The spelling of 132262003401050 in words is "one hundred thirty-two trillion, two hundred sixty-two billion, three million, four hundred one thousand, fifty".
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