Base | Representation |
---|---|
bin | 111101100110111101… |
… | …1110101001001010100 |
3 | 110122111111101012210221 |
4 | 1323031323311021110 |
5 | 4131424313013330 |
6 | 140440222324124 |
7 | 12362421501544 |
oct | 1731573651124 |
9 | 418444335727 |
10 | 132304032340 |
11 | 511231a4797 |
12 | 21784429644 |
13 | c62632c18c |
14 | 65914a7324 |
15 | 369527eb7a |
hex | 1ecdef5254 |
132304032340 has 24 divisors (see below), whose sum is σ = 279543005280. Its totient is φ = 52596939168.
The previous prime is 132304032271. The next prime is 132304032349. The reversal of 132304032340 is 43230403231.
It is a super-3 number, since 3×1323040323403 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132304032349) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20288770 + ... + 20295289.
It is an arithmetic number, because the mean of its divisors is an integer number (11647625220).
Almost surely, 2132304032340 is an apocalyptic number.
132304032340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132304032340 is an abundant number, since it is smaller than the sum of its proper divisors (147238972940).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132304032340 is a wasteful number, since it uses less digits than its factorization.
132304032340 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40584231 (or 40584229 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 132304032340 its reverse (43230403231), we get a palindrome (175534435571).
The spelling of 132304032340 in words is "one hundred thirty-two billion, three hundred four million, thirty-two thousand, three hundred forty".
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