Base | Representation |
---|---|
bin | 11110000101010010111100… |
… | …011001101101101011110111 |
3 | 122100110021012011121011021202 |
4 | 132011102330121231223313 |
5 | 114320142310330141234 |
6 | 1145220121530203115 |
7 | 36603513333515501 |
oct | 3605227431555367 |
9 | 570407164534252 |
10 | 132305333443319 |
11 | 3917a416599203 |
12 | 12a097b058349b |
13 | 58a94548b3b7a |
14 | 249588024cd71 |
15 | 10468730a477e |
hex | 7854bc66daf7 |
132305333443319 has 2 divisors, whose sum is σ = 132305333443320. Its totient is φ = 132305333443318.
The previous prime is 132305333443259. The next prime is 132305333443321. The reversal of 132305333443319 is 913344333503231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132305333443319 is a prime.
It is a super-2 number, since 2×1323053334433192 (a number of 29 digits) contains 22 as substring.
It is a Sophie Germain prime.
Together with 132305333443321, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132305333443379) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66152666721659 + 66152666721660.
It is an arithmetic number, because the mean of its divisors is an integer number (66152666721660).
Almost surely, 2132305333443319 is an apocalyptic number.
132305333443319 is a deficient number, since it is larger than the sum of its proper divisors (1).
132305333443319 is an equidigital number, since it uses as much as digits as its factorization.
132305333443319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3149280, while the sum is 47.
The spelling of 132305333443319 in words is "one hundred thirty-two trillion, three hundred five billion, three hundred thirty-three million, four hundred forty-three thousand, three hundred nineteen".
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