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132311342301440 = 285293564421937
BaseRepresentation
bin11110000101011000100010…
…100011101100000100000000
3122100110211200221022210000112
4132011120202203230010000
5114320242112112121230
61145222554101010452
736604115256126341
oct3605304243540400
9570424627283015
10132311342301440
1139181a1a41a255
1212a0a9a89b3a28
1358a9ba1761813
142495c902c60c8
151046ac588bd95
hex7856228ec100

132311342301440 has 72 divisors (see below), whose sum is σ = 327855529857240. Its totient is φ = 51099552874496.

The previous prime is 132311342301379. The next prime is 132311342301493. The reversal of 132311342301440 is 44103243113231.

132311342301440 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 7814305886464 + 124497036414976 = 2795408^2 + 11157824^2 .

It is a Harshad number since it is a multiple of its sum of digits (32).

It is a junction number, because it is equal to n+sod(n) for n = 132311342301397 and 132311342301406.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1782173849 + ... + 1782248088.

It is an arithmetic number, because the mean of its divisors is an integer number (4553549025795).

Almost surely, 2132311342301440 is an apocalyptic number.

132311342301440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

132311342301440 is an abundant number, since it is smaller than the sum of its proper divisors (195544187555800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132311342301440 is an equidigital number, since it uses as much as digits as its factorization.

132311342301440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3564421987 (or 3564421973 counting only the distinct ones).

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 132311342301440 its reverse (44103243113231), we get a palindrome (176414585414671).

The spelling of 132311342301440 in words is "one hundred thirty-two trillion, three hundred eleven billion, three hundred forty-two million, three hundred one thousand, four hundred forty".

Divisors: 1 2 4 5 8 10 16 20 29 32 40 58 64 80 116 128 145 160 232 256 290 320 464 580 640 928 1160 1280 1856 2320 3712 4640 7424 9280 18560 37120 3564421937 7128843874 14257687748 17822109685 28515375496 35644219370 57030750992 71288438740 103368236173 114061501984 142576877480 206736472346 228123003968 285153754960 413472944692 456246007936 516841180865 570307509920 826945889384 912492015872 1033682361730 1140615019840 1653891778768 2067364723460 2281230039680 3307783557536 4134729446920 4562460079360 6615567115072 8269458893840 13231134230144 16538917787680 26462268460288 33077835575360 66155671150720 132311342301440