Base | Representation |
---|---|
bin | 11110000101011010001100… |
… | …100001100001110011000000 |
3 | 122100111000021211121022121101 |
4 | 132011122030201201303000 |
5 | 114320304232222320000 |
6 | 1145223450325504144 |
7 | 36604210314261001 |
oct | 3605321441416300 |
9 | 570430254538541 |
10 | 132313120120000 |
11 | 39182751a03696 |
12 | 12a0b204272054 |
13 | 58aa0c5b86571 |
14 | 2495dbc4671a8 |
15 | 1046b7b9b2e6a |
hex | 78568c861cc0 |
132313120120000 has 140 divisors (see below), whose sum is σ = 328179115173096. Its totient is φ = 52911443200000.
The previous prime is 132313120119953. The next prime is 132313120120007. The reversal of 132313120120000 is 21021313231.
It is a self number, because there is not a number n which added to its sum of digits gives 132313120120000.
It is not an unprimeable number, because it can be changed into a prime (132313120120007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 153610524 + ... + 154469476.
Almost surely, 2132313120120000 is an apocalyptic number.
132313120120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 132313120120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (164089557586548).
132313120120000 is an abundant number, since it is smaller than the sum of its proper divisors (195865995053096).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132313120120000 is an frugal number, since it uses more digits than its factorization.
132313120120000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 862836 (or 862811 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 132313120120000 its reverse (21021313231), we get a palindrome (132334141433231).
The spelling of 132313120120000 in words is "one hundred thirty-two trillion, three hundred thirteen billion, one hundred twenty million, one hundred twenty thousand".
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