Base | Representation |
---|---|
bin | 10011010000010000111… |
… | …000010001011010101110 |
3 | 11200111020102101101221021 |
4 | 103100100320101122232 |
5 | 133134234034122110 |
6 | 2451501114324354 |
7 | 164410320621460 |
oct | 23202070213256 |
9 | 4614212341837 |
10 | 1323133114030 |
11 | 470157170152 |
12 | 1945227296ba |
13 | 97a039225b0 |
14 | 4807ba08130 |
15 | 2463ec7b2da |
hex | 13410e116ae |
1323133114030 has 64 divisors (see below), whose sum is σ = 2932053344640. Its totient is φ = 418634878464.
The previous prime is 1323133114013. The next prime is 1323133114063. The reversal of 1323133114030 is 304113313231.
It is a junction number, because it is equal to n+sod(n) for n = 1323133113986 and 1323133114004.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3148356 + ... + 3543784.
It is an arithmetic number, because the mean of its divisors is an integer number (45813333510).
Almost surely, 21323133114030 is an apocalyptic number.
1323133114030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1323133114030 is an abundant number, since it is smaller than the sum of its proper divisors (1608920230610).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1323133114030 is a wasteful number, since it uses less digits than its factorization.
1323133114030 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 399133.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 1323133114030 its reverse (304113313231), we get a palindrome (1627246427261).
The spelling of 1323133114030 in words is "one trillion, three hundred twenty-three billion, one hundred thirty-three million, one hundred fourteen thousand, thirty".
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