Base | Representation |
---|---|
bin | 1100000010010001010011… |
… | …1100001001100111110110 |
3 | 1201212002001122222200101212 |
4 | 3000210110330021213312 |
5 | 3213302440230120400 |
6 | 44051120110521422 |
7 | 2534030453161034 |
oct | 300442474114766 |
9 | 51762048880355 |
10 | 13233145551350 |
11 | 424216674923a |
12 | 1598809806272 |
13 | 74cb59c55c6a |
14 | 33a6b8205554 |
15 | 17e35797a335 |
hex | c0914f099f6 |
13233145551350 has 48 divisors (see below), whose sum is σ = 26069384519568. Its totient is φ = 4980385290240.
The previous prime is 13233145551319. The next prime is 13233145551377. The reversal of 13233145551350 is 5315554133231.
It is a super-2 number, since 2×132331455513502 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13233145551298 and 13233145551307.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 466457 + ... + 5165643.
It is an arithmetic number, because the mean of its divisors is an integer number (543112177491).
Almost surely, 213233145551350 is an apocalyptic number.
13233145551350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13233145551350 is a deficient number, since it is larger than the sum of its proper divisors (12836238968218).
13233145551350 is a wasteful number, since it uses less digits than its factorization.
13233145551350 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4702529 (or 4702524 counting only the distinct ones).
The product of its (nonzero) digits is 405000, while the sum is 41.
Adding to 13233145551350 its reverse (5315554133231), we get a palindrome (18548699684581).
The spelling of 13233145551350 in words is "thirteen trillion, two hundred thirty-three billion, one hundred forty-five million, five hundred fifty-one thousand, three hundred fifty".
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