Base | Representation |
---|---|
bin | 11110000101101101010001… |
… | …100111100000000100110110 |
3 | 122100112222011120122201020201 |
4 | 132011231101213200010312 |
5 | 114321123211301312200 |
6 | 1145241115235351114 |
7 | 36605534065116652 |
oct | 3605552147400466 |
9 | 570488146581221 |
10 | 132333606666550 |
11 | 391904050402a3 |
12 | 12a1318115249a |
13 | 58ac00c2b5863 |
14 | 2496da3201a62 |
15 | 104747a2dac6a |
hex | 785b519e0136 |
132333606666550 has 24 divisors (see below), whose sum is σ = 246140943516000. Its totient is φ = 52933349093280.
The previous prime is 132333606666539. The next prime is 132333606666551. The reversal of 132333606666550 is 55666606333231.
It is a junction number, because it is equal to n+sod(n) for n = 132333606666491 and 132333606666500.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132333606666551) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 30905776 + ... + 34926124.
It is an arithmetic number, because the mean of its divisors is an integer number (10255872646500).
Almost surely, 2132333606666550 is an apocalyptic number.
132333606666550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132333606666550 is a deficient number, since it is larger than the sum of its proper divisors (113807336849450).
132333606666550 is a wasteful number, since it uses less digits than its factorization.
132333606666550 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4678680 (or 4678675 counting only the distinct ones).
The product of its (nonzero) digits is 31492800, while the sum is 55.
The spelling of 132333606666550 in words is "one hundred thirty-two trillion, three hundred thirty-three billion, six hundred six million, six hundred sixty-six thousand, five hundred fifty".
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