Base | Representation |
---|---|
bin | 111101101000000011… |
… | …0100100010010010100 |
3 | 110122121000210221122110 |
4 | 1323100012210102110 |
5 | 4132013120320200 |
6 | 140444002031020 |
7 | 12363342564522 |
oct | 1732006442224 |
9 | 418530727573 |
10 | 132340401300 |
11 | 51141785288 |
12 | 21794648470 |
13 | c630a24083 |
14 | 6596253312 |
15 | 3698565b50 |
hex | 1ed01a4494 |
132340401300 has 36 divisors (see below), whose sum is σ = 382904895296. Its totient is φ = 35290773600.
The previous prime is 132340401299. The next prime is 132340401353. The reversal of 132340401300 is 3104043231.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 220567036 + ... + 220567635.
Almost surely, 2132340401300 is an apocalyptic number.
132340401300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132340401300 is an abundant number, since it is smaller than the sum of its proper divisors (250564493996).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132340401300 is a wasteful number, since it uses less digits than its factorization.
132340401300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 441134688 (or 441134681 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 21.
Adding to 132340401300 its reverse (3104043231), we get a palindrome (135444444531).
The spelling of 132340401300 in words is "one hundred thirty-two billion, three hundred forty million, four hundred one thousand, three hundred".
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