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132344410021 is a prime number
BaseRepresentation
bin111101101000001010…
…1110110111110100101
3110122121022100121120121
41323100111312332211
54132020132110041
6140444224001541
712363421631665
oct1732025667645
9418538317517
10132344410021
1151143a7307a
1221795a602b1
13c6317c88b5
1465969b81a5
153698aa87d1
hex1ed0576fa5

132344410021 has 2 divisors, whose sum is σ = 132344410022. Its totient is φ = 132344410020.

The previous prime is 132344410019. The next prime is 132344410031. The reversal of 132344410021 is 120014443231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 107289002500 + 25055407521 = 327550^2 + 158289^2 .

It is an emirp because it is prime and its reverse (120014443231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132344410021 - 21 = 132344410019 is a prime.

Together with 132344410019, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132344410031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66172205010 + 66172205011.

It is an arithmetic number, because the mean of its divisors is an integer number (66172205011).

Almost surely, 2132344410021 is an apocalyptic number.

It is an amenable number.

132344410021 is a deficient number, since it is larger than the sum of its proper divisors (1).

132344410021 is an equidigital number, since it uses as much as digits as its factorization.

132344410021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 132344410021 its reverse (120014443231), we get a palindrome (252358853252).

The spelling of 132344410021 in words is "one hundred thirty-two billion, three hundred forty-four million, four hundred ten thousand, twenty-one".