Base | Representation |
---|---|
bin | 1100000010011000101110… |
… | …0010111110010110111010 |
3 | 1201212021012100022111220010 |
4 | 3000212023202332112322 |
5 | 3213321024133042224 |
6 | 44052045353042350 |
7 | 2534130665021424 |
oct | 300461342762672 |
9 | 51767170274803 |
10 | 13235135440314 |
11 | 4242a97a0a277 |
12 | 15990840b63b6 |
13 | 7500b62a0058 |
14 | 33a8265cb814 |
15 | 17e4224e1e29 |
hex | c098b8be5ba |
13235135440314 has 64 divisors (see below), whose sum is σ = 30785185244160. Its totient is φ = 3762633726720.
The previous prime is 13235135440313. The next prime is 13235135440369. The reversal of 13235135440314 is 41304453153231.
13235135440314 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not an unprimeable number, because it can be changed into a prime (13235135440313) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 148417932 + ... + 148507079.
It is an arithmetic number, because the mean of its divisors is an integer number (481018519440).
Almost surely, 213235135440314 is an apocalyptic number.
13235135440314 is an abundant number, since it is smaller than the sum of its proper divisors (17550049803846).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13235135440314 is a wasteful number, since it uses less digits than its factorization.
13235135440314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 296925075.
The product of its (nonzero) digits is 259200, while the sum is 39.
Adding to 13235135440314 its reverse (41304453153231), we get a palindrome (54539588593545).
The spelling of 13235135440314 in words is "thirteen trillion, two hundred thirty-five billion, one hundred thirty-five million, four hundred forty thousand, three hundred fourteen".
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